جاوا :
کد:
Random rd = new Random();
rd.nextInt(101);
int hesam , hadi;
for(hesam = rd.nextInt(101) , hadi=rd.nextInt(101)
; hesam <=1000 || hadi <=1000;
hesam+=rd.nextInt(11) , hadi+=rd.nextInt(11)){
System.out.println("Hesam number is " + hesam+
"Hadi number is "+ hadi);
}
if(hesam > hadi){
System.out.println("Hesam Won "+ hesam);
}else if(hesam < hadi){
System.out.println("Hadi Won "+ hadi);
}else {
System.out.println("Both Win :) +");
}
}
کد:
Hesam number is 977Hadi number is 1005
Hesam number is 981Hadi number is 1014
Hesam number is 981Hadi number is 1014
Hesam number is 985Hadi number is 1015
Hesam number is 993Hadi number is 1024
Hesam number is 1000Hadi number is 1034
Hesam number is 1000Hadi number is 1035
Hadi Won 1042
اندورید :
کد:
Button btn =(Button)findViewById(R.id.button1);
btn.setOnClickListener(new OnClickListener() {
@Override
public void onClick(View arg0) {
TextView txt1 = (TextView)findViewById(R.id.textView1);
TextView txt2 = (TextView)findViewById(R.id.textView2);
Random rd = new Random();
rd.nextInt(101);
int hesam , hadi;
for(hesam = rd.nextInt(101) , hadi=rd.nextInt(101)
; hesam <=1000 || hadi <=1000;
hesam+=rd.nextInt(11) , hadi+=rd.nextInt(11)){
txt1.setText("Hesam number is " + hesam+
"Hadi number is "+ hadi + "n");
}
if(hesam > hadi){
txt2.setText("Hesam Won "+ hesam);
}else if(hesam < hadi){
txt2.setText("Hadi Won "+ hadi);
}else {
txt2.setText("Both Win");
} }
});
خروجی :
کد:
Hesam number is 1000Hadi number is 1035Hadi Won 1042
میخواستم اگه امکانش هست راهنمایی کنید
که چیکار کنم TextView مثل Println عمل کنم
برچسب:
نویسنده: کاوه محمدزادگان